A charged particle of charge q and mass m enters perpendicularly in a magnetic field 
. Kinetic energy of the particle is E; then frequency of rotation is:
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
B
For a charged particle to move in a circular path in a magnetic field, the magnetic force on charge particle provides the necessary centripetal force.
hence, magnetic force = centripetal force
i.e., qvB = 
or qvB = mrω 2 (v = rω)
or ω 2 = 
or ω = 
If n is the frequency of rotation, then
ω = 2πn
⇒ n = 
= 
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